PROPOSITION 20.
In a circle the angle at the centre is double of the angle at the circumference, when the angles have the same circumference as base. Let ABC be a circle, let the angle BEC be an angleat its centre, and the angle BAC an angle at the circumference, and let them have the same circumference BC as base; I say that the angle BEC is double of
the angle BAC. For let AE be joined and drawn through to F. Then, since EA is equal to EB,
EAB. For the same reason
Again let another straight line be inflected, and let there be another angle BDC; let DE be joined and produced to G. Similarly then we can prove that the angle GEC is double of the angle EDC,

