I say that CD is binomial and the same in order with AB.
For, since AB is binomial, let it be divided into its terms at E, and let AE be the greater term; therefore AE, EB are rational straight lines commensurable in square only. [[X. 36](elem.10.36)]

Let it be contrived that, as AB is to CD, so is AE to CF; [[VI. 12](elem.6.12)] therefore also the remainder EB is to the remainder FD as AB is to CD. [[V. 19](elem.5.19)]

But AB is commensurable in length with CD; therefore AE is also commensurable with CF, and EB with FD. [[X. 11](elem.10.11)]

And AE, EB are rational; therefore CF, FD are also rational.

And, as AE is to CF, so is EB to FD. [[V. 11](elem.5.11)]

Therefore, alternately, as AE is to EB, so is CF to FD. [[V. 16](elem.5.16)]

But AE, EB are commensurable in square only; therefore CF, FD are also commensurable in square only. [[X. 11](elem.10.11)]

And they are rational; therefore CD is binomial. [[X. 36](elem.10.36)]

I say next that it is the same in order with AB.

For the square on AE is greater than the square on EB either by the square on a straight line commensurable with AE or by the square on a straight line incommensurable with it.

If then the square on AE is greater than the square on EB by the square on a straight line commensurable with AE, the square on CF will also be greater than the square on FD by the square on a straight line commensurable with CF. [[X. 14](elem.10.14)]

And, if AE is commensurable with the rational straight line set out, CF will also be commensurable with it, [[X. 12](elem.10.12)] and for this reason each of the straight lines AB, CD is a first binomial, that is, the same in order. [[X. Deff. II. 1](elem.10.def.2.1)]

But, if EB is commensurable with the rational straight line set out, FD is also commensurable with it, [[X. 12](elem.10.12)] and for this reason again CD will be the same in order with AB, for each of them will be a second binomial. [[X. Deff. II. 2](elem.10.def.2.2)]

But, if neither of the straight lines AE, EB is commensurable with the rational straight line set out, neither of the straight lines CF, FD will be commensurable with it, [[X. 13](elem.10.13)] and each of the straight lines AB, CD is a third binomial. [[X. Deff. II. 3](elem.10.def.2.3)]

But, if the square on AE is greater than the square on EB by the square on a straight line incommensurable with AE, the square on CF is also greater than the square on FD by the square on a straight line incommensurable with CF. [[X. 14](elem.10.14)]

And, if AE is commensurable with the rational straight line set out, CF is also commensurable with it, and each of the straight lines AB, CD is a fourth binomial. [[X. Deff. II. 4](elem.10.def.2.4)]

But, if EB is so commensurable, so is FD also, and each of the straight lines AB, CD will be a fifth binomial. [[X. Deff. II. 5](elem.10.def.2.5)]

But, if neither of the straight lines AE, EB is so commensurable, neither of the straight lines CF, FD is commensurable with the rational straight line set out, and each of the straight lines AB, CD will be a sixth binomial. [[X. Deff. II. 6](elem.10.def.2.6)]

Hence a straight line commensurable in length with a binomial straight line is binomial and the same in order. Q. E. D.