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<TEI.2><text><body><div1 n="10" type="book" org="uniform" sample="complete"><div2 n="Prop 3" type="type" org="uniform" sample="complete"><div3 id="elem.10.108" n="108" type="number" org="uniform" sample="complete">
      <head>PROPOSITION 108.</head>
      <p><hi rend="ital">If from a rational area a medial area be subtracted, the <quote>side</quote>
 of the remaining area becomes one of two irrational straight lines, either an apotome or a minor straight line</hi>. </p>
      <p>For from the rational area <hi rend="ital">BC</hi> let the medial area <hi rend="ital">BD</hi> be subtracted; I say that the <quote>side</quote>
 of the remainder <hi rend="ital">EC</hi> becomes one of two irrational straight lines, either an apotome or a minor straight line. <figure />
      </p>
      <p>For let a rational straight line <hi rend="ital">FG</hi> be set out, to <hi rend="ital">FG</hi> let there be applied the rectangular parallelogram <hi rend="ital">GH</hi> equal to <hi rend="ital">BC</hi>, and let <hi rend="ital">GK</hi> equal to <hi rend="ital">DB</hi> be subtracted; therefore the remainder <hi rend="ital">EC</hi> is equal to <hi rend="ital">LH</hi>. </p>
      <p>Since then <hi rend="ital">BC</hi> is rational, and <hi rend="ital">BD</hi> medial, while <hi rend="ital">BC</hi> is equal to <hi rend="ital">GH</hi>, and <hi rend="ital">BD</hi> to <hi rend="ital">GK</hi>, therefore <hi rend="ital">GH</hi> is rational, and <hi rend="ital">GK</hi> medial. </p>
      <p>And they are applied to the rational straight line <hi rend="ital">FG</hi>; therefore <hi rend="ital">FH</hi> is rational and commensurable in length with <hi rend="ital">FG</hi>, [<ref target="elem.10.20" targOrder="U">X. 20</ref>] while <hi rend="ital">FK</hi> is rational and incommensurable in length with <hi rend="ital">FG</hi>; [<ref target="elem.10.22" targOrder="U">X. 22</ref>] therefore <hi rend="ital">FH</hi> is incommensurable in length with <hi rend="ital">FK</hi>. [<ref target="elem.10.13" targOrder="U">X. 13</ref>] </p>
      <p>Therefore <hi rend="ital">FH</hi>, <hi rend="ital">FK</hi> are rational straight lines commensurable in square only; therefore <hi rend="ital">KH</hi> is an apotome [<ref target="elem.10.73" targOrder="U">X. 73</ref>], and <hi rend="ital">KF</hi> the annex to it. </p>
      <p>Now the square on <hi rend="ital">HF</hi> is greater than the square on <hi rend="ital">FK</hi> by the square on a straight line either commensurable with <hi rend="ital">HF</hi> or not commensurable. </p>
      <p>First, let the square on it be greater by the square on a straight line commensurable with it. </p>
      <p>Now the whole <hi rend="ital">HF</hi> is commensurable in length with the rational straight line <hi rend="ital">FG</hi> set out; therefore <hi rend="ital">KH</hi> is a first apotome. [<ref target="elem.10.def.3.1" targOrder="U">X. Deff. III. 1</ref>] <pb n="236" /></p>
      <p>But the <quote>side</quote>
 of the rectangle contained by a rational straight line and a first apotome is an apotome. [<ref target="elem.10.91" targOrder="U">X. 91</ref>] </p>
      <p>Therefore the <quote>side</quote>
 of <hi rend="ital">LH</hi>, that is, of <hi rend="ital">EC</hi>, is an apotome. </p>
      <p>But, if the square on <hi rend="ital">HF</hi> is greater than the square on <hi rend="ital">FK</hi> by the square on a straight line incommensurable with <hi rend="ital">HF</hi>, while the whole <hi rend="ital">FH</hi> is commensurable in length with the rational straight line <hi rend="ital">FG</hi> set out, <hi rend="ital">KH</hi> is a fourth apotome. [<ref target="elem.10.def.3.4" targOrder="U">X. Deff. III. 4</ref>] </p>
      <p>But the <quote>side</quote>
 of the rectangle contained by a rational straight line and a fourth apotome is minor. [<ref target="elem.10.94" targOrder="U">X. 94</ref>] Q. E. D.</p>
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