Statistics for occurrence #1 of “Milford” in entry scammel-alexander of Harper's Encyclopedia of United States History:

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Military officer; born in Mendon (now Milford ), Mass., March 24, 1747; graduated at Harvard College in 1769; taught school, practised surveying, and became proprietor of the town of Shapleigh, Me. In 1775 he was studying law with General Sulliva...
Max. Freq. Min. Freq.
Entity Corpus Doc Corpus Doc  
Milford (New Jersey, United States) 604 104 158 36 0 user votes
Milford (Pennsylvania, United States) 13 0 1 0 0 user votes
Milford (Delaware, United States) 6 0 2 0 0 user votes
Milford (Kentucky, United States) 3 0 1 0 0 user votes
Milford (Georgia, United States) 1 0 1 0 0 user votes
Milford (Arkansas, United States) 0 0 0 0 0 user votes
Milford (California, United States) 0 0 0 0 0 user votes
Milford (Illinois, United States) 0 0 0 0 0 user votes
Milford (Indiana, United States) 0 0 0 0 0 user votes
Milford (Indiana, United States) 0 0 0 0 0 user votes
Milford (Iowa, United States) 0 0 0 0 0 user votes
Milford (Louisiana, United States) 0 0 0 0 0 user votes
Milford (Maine, United States) 0 0 0 0 0 user votes
Milford (Maryland, United States) 0 0 0 0 0 user votes
Milford (Michigan, United States) 0 0 0 0 0 user votes
Milford (Nebraska, United States) 0 0 0 0 0 user votes
Milford (New Jersey, United States) 0 0 0 0 0 user votes
Milford (New York, United States) 0 0 0 0 0 user votes
Milford (Pennsylvania, United States) 0 0 0 0 0 user votes
Milford (South Carolina, United States) 0 0 0 0 0 user votes
Milford (South Carolina, United States) 0 0 0 0 0 user votes
Milford (Texas, United States) 0 0 0 0 0 user votes
Milford (United Kingdom) 0 0 0 0 0 user votes
Milford (Utah, United States) 0 0 0 0 0 user votes
Milford (Wisconsin, United States) 0 0 0 0 0 user votes
Milford (Wyoming, United States) 0 0 0 0 0 user votes

† This entity has been selected by the automated classifier as the most likely match in this context. It may or may not be the correct match.